Which of the following is correctly matched?

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(B) $1$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$. It undergoes $dsp^2$ hybridization and is paramagnetic due to one unpaired electron.$2$. For $K_

Vedclass · Accepted Answer

$K_2[Ni(CN)_4]$: $dsp^2$,diamagnetic

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(B) $1$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$. It undergoes $dsp^2$ hybridization and is paramagnetic due to one unpaired electron.$2$. For $K_2[Ni(CN)_4]$,$Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons. It undergoes $dsp^2$ hybridization and is diamagnetic.$3$. $[Co(NH_3)_4(H_2O)_2]Cl_3$ involves $Co^{3+}$ $(3d^6)$. With weak field ligands,it undergoes $sp^3d^2$ hybridization and is paramagnetic.$4$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex ($dsp^2$ hybridization) and is diamagnetic.Therefore,option $B$ is correctly matched.

List-$I$ (Complex/Species)	List-$II$ (Shape and magnetic moment)
$A$. $[Ni(CO)_4]$	$I$. Tetrahedral,$2.8 \ BM$
$B$. $[Ni(CN)_4]^{2-}$	$II$. Square planar,$0 \ BM$
$C$. $[NiCl_4]^{2-}$	$III$. Tetrahedral,$0 \ BM$
$D$. $[MnBr_4]^{2-}$	$IV$. Tetrahedral,$5.9 \ BM$

$A. sp^3$	$(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$	$(ii). [Ni(CO)_4]$
$C. sp^3d^2$	$(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$	$(iv). [CoF_6]^{3-}$
	$(v). [Fe(CO)_5]$

Similar Questions

Match the following hybridization in Column $I$ with the corresponding coordination complexes in Column $II$.
$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$ $(ii). [Ni(CO)_4]$
$C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$ $(iv). [CoF_6]^{3-}$
$(v). [Fe(CO)_5]$

Both $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ are diamagnetic. The types of hybridisation of $Ni$ in these complexes are . . . . . . and . . . . . . respectively.

Why is $[CoF_6]^{3-}$ considered an outer orbital complex?

Which of the following systems in an octahedral complex has the maximum number of unpaired electrons?

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